4v^2-4=15v

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Solution for 4v^2-4=15v equation:


Simplifying
4v2 + -4 = 15v

Reorder the terms:
-4 + 4v2 = 15v

Solving
-4 + 4v2 = 15v

Solving for variable 'v'.

Reorder the terms:
-4 + -15v + 4v2 = 15v + -15v

Combine like terms: 15v + -15v = 0
-4 + -15v + 4v2 = 0

Factor a trinomial.
(-1 + -4v)(4 + -1v) = 0

Subproblem 1

Set the factor '(-1 + -4v)' equal to zero and attempt to solve: Simplifying -1 + -4v = 0 Solving -1 + -4v = 0 Move all terms containing v to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -4v = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -4v = 0 + 1 -4v = 0 + 1 Combine like terms: 0 + 1 = 1 -4v = 1 Divide each side by '-4'. v = -0.25 Simplifying v = -0.25

Subproblem 2

Set the factor '(4 + -1v)' equal to zero and attempt to solve: Simplifying 4 + -1v = 0 Solving 4 + -1v = 0 Move all terms containing v to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1v = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1v = 0 + -4 -1v = 0 + -4 Combine like terms: 0 + -4 = -4 -1v = -4 Divide each side by '-1'. v = 4 Simplifying v = 4

Solution

v = {-0.25, 4}

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